UN Fisika 2016 Paket 2 Nomor 39

Perhatikan reaksi inti berikut!

4{}_{1}^{1}H\to ~{}_{2}^{4}He+2{}_{1}^{0}e+Q

Diketahui:

{}_{1}^{1}H=1,0081~sma

{}_{2}^{4}He=4,0038~sma

{}_{1}^{0}e=sangat~kecil~\left( diabaikan \right)

Jika 1 sma = 931 MeV, berapa energi yang dihasilkan pada reaksi inti di atas?

A.    0,00286 MeV D.    40,2832 MeV
B.     26,6266 MeV E.     92,2431 MeV
C.     35,3781 MeV

Penyelesaian

Energi ikat inti.

E=\text{ }\!\!\Delta\!\!\text{ }m.{{c}^{2}}

E=\text{ }\!\!\Delta\!\!\text{ }m.~931~MeV

E=\left\{ 4\left( 1,0081 \right)-\left( 4,0038 \right) \right\}\times 931~MeV

E=26,6266~MeV

jawaban B

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