UN Fisika 2016 Paket 2 Nomor 22

Dalam sebuah bejana yang tertutup rapat berisi gas ideal. Jika tekanan gas ideal dijadikan 3 kali semula dan volumenya 2x semula, maka sehu gas menjadi …

A.    1,5 kali semula D. 5 kali semula
B.     3 kali semula E. 6 kali semula
C.     4,5 kali semula

Penyelesaian

Hukum Boyle Charles Gay-Lussac

\frac{PV}{T}=konstan

\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}

\frac{PV}{T}=\frac{3P~.~~2V}{{{T}_{2}}}

{{T}_{2}}=6T

jawaban E

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